
Displacement
Answers
A fullsized glider has a glide angle of 2 degrees. If it loses 50 meters
of altitude, how far would it move horizontally?
Tan 2^{o} = 50/x
Therefore, x = 50/Tan 2^{o} = 1432
m
A model glider moves horizontally 12 meters for every meter of altitude
it loses. What is it's glide angle?
Tan A = 1/12
Therefore, LA = 4.8^{o}
A model glider has a glide angle of 5 degrees. If it flies 23 meters
horizontally, how much altitude will it lose?
Tan 5^{o} = X/23
X = 23 (Tan 5^{o}) = 2 m
A fullsized glider has a glide angle of 5 degrees. If the altitude
is 300 meters, will the glider make it to an airport 4,000 meters away?
Tan 5^{o} = 300/X
X= 300/Tan 5^{o} = 3,429 m (Note:
Will not make it to the airport 4,000 m away.)
A fullsized glider loses 2 meters for every 38 meters it travels horizontally.
What is it's glide angle?
Tan LA = 2/38
Therefore, LA = 3.0^{o}
A model glider travels 57 meters horizontally after losing 5 meters
of altitude. What is it's glide angle?
Tan LA = 5/57
Therefore, LA = 5.0^{o}
A model glider loses 3 meters of altitude. If it has a glide angle of
4 degrees, how far did the glider travel horizontally?
Tan 4^{o} = 3/X
X = 3/Tan 4^{o}
X = 42.9 m
A fullsized glider lands 10,000 meters horizontally from where it began
its downward diagonal path. If the glide angle is 3 degrees, what was
the glider's altitude?
Tan 3^{o} = X/10,000
X = (10,000)(Tan 3^{o})
X = 524 m
 A model glider
has an average velocity of 2.2 m/s along it's downward diagonal path.
After 10 seconds, the glider has lost 2 meters of altitude. What is
the glider's glide angle and how far horizontally did it travel?
d = Vt (Note: a = 0)
d = (2.2)(10) = 22 m (hyp)
Sin LA = 2/22
Therefore, LA = 5.2^{o}
22^{2} = 2^{2} + X^{2}
X = sq. root of (22^{2}  2^{2)} = 21.9
m
A fullsized
glider has a velocity of 36 m/s along it's downward diagonal path. If
it has a glide angle of 4 degrees, how much altitude will it lose in
2 minutes? How far will it travel horizontally in that 2 minutes?
d = Vt (Note: a = 0)
d = 36 (120s) = 4,320 m
Sin 4^{o} = a/4320
a = (4320)(Sin 4) = 301 m
Cos
4^{o} = d/4320
Therefore, d = (4320)(Cos 4) = 4,309 m
