Problem Three:
In this problem, we are asked to find the area of a right triangle with an acute
angle at the origin, an acute angle at the point, "fifty
twenty-five,"
and a right angle on the x-axis. The area is one half of the product base-times-height.
You may work this number out for yourselves.
Using the integral calculus, we are asked to find the area between the x-axis
and the line from the origin to the point, "fifty
twenty-five."
The equation of this line is, "y equals fifty-over-twenty-five x," which
simplifies to, "y equals one-half x." The corresponding integral is,
"The integral from x-equals-zero to x-equals-fifty of one-half-x-dee-x."
The value of this integral, using feet for our unit of measure, is six-hundred-and-twenty-five
square feet.