|
Velocity Effects
Answers
|
|
- Go to the Foilsim
Software Program and set initial conditions as follows: Airspeed(velocity)
= 50 km/h, Altitude = 5000 m, Angle = 1 deg , Thickness = 12.5, Camber
= 12.5, Area = 5 sq. m.
What is the Lift?
595 Newtons
- Change the velocity(airspeed)
as shown in the following table and record the associated lift for each
velocity to complete the table.
Velocity(km/h)
- Airspeed
|
Lift(Newtons)
|
50
|
595
|
100
|
2,378
|
150
|
5,351
|
200
|
9,513
|
250
|
14,860
|
300
|
21,400
|
400
|
38,050
|
TABLE 1
- Construct a graph
of Velocity's effect on Lift with an Independent Variable(X) of Velocity
and a Dependent Variable(Y) of Lift. Label each axis correctly to include
units. Print out graph from Foilsim Program...
- What is the shape
of the curve formed by this relationship? Parabolic
Shape
- Write the equation
for this relationship! y = cx2__Where
y = lift, and x = airspeed_and c = a constant
- What is the value
of the constant in this equation for this set of conditions?
C = .23784
Newtons/kph2
- Interpolate the
lift for a velocity of 350 kph. What is the lift? 29,130
Newtons
- Extrapolate the
lift for a velocity of 500 kph. What is the lift?
59,460 Newtons
- Based on the relationship
between lift and velocity, how would you increase the lift on a wing?
Increase the Velocity
- Set the initial
conditions provided in Problem 1 above and assume: g = 9.8 m./sec.2
at this elevation; total weight of airplane, cargo, and fuel =
5000 kg.; weight of airplane = 3000 kg. ; weight of cargo and fuel =
2000 kg. Use the equation for lift that you generated in Problem 5 to
answer these questions:
- What
is the lift in Newtons required to maintain altitude in these
conditions?
49,000
Newtons
- What is the
velocity that is required to maintain this lift?
454
kph
- One hour later
all cargo is parachuted off the airplane and 200 kg. of fuel remains.
- What
is the lift in Newtons now required to maintain altitude?
31,360
Newtons
- What is the
velocity that is now required to generate the lift?
363
kph
|